useNumericLiterals

诊断类别：lint/style/useNumericLiterals

¥Diagnostic Category: lint/style/useNumericLiterals

JavaScript (and super languages)

自从：v1.0.0

¥Since: v1.0.0

来源：

¥Sources:

与以下相同：prefer-numeric-literals

¥Same as: prefer-numeric-literals

禁止 parseInt() 和 Number.parseInt()，转而使用二进制、八进制和十六进制文字

¥Disallow parseInt() and Number.parseInt() in favor of binary, octal, and hexadecimal literals

JavaScript 为二进制、八进制和十六进制数字提供文字形式。例如：0b11、0o77 和 0xff。使用文字形式可启用静态代码分析并避免不必要的计算。

¥JavaScript provides literal forms for binary, octal, and hexadecimal numbers. For example: 0b11, 0o77, and 0xff. Using the literal forms enable static code analysis and avoid unnecessary computations.

示例

¥Examples

无效

¥Invalid

parseInt("111110111", 2);

code-block.js:1:1 lint/style/useNumericLiterals  FIXABLE  ━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

  ✖ This call to parseInt() can be replaced by a binary literal.
  
  > 1 │ parseInt(“111110111”, 2);
      │ ^^^^^^^^^^^^^^^^^^^^^^^^
    2 │ 
  
  ℹ Using a literal avoids unnecessary computations.
  
  ℹ Unsafe fix: Use the computed binary literal instead.
  
    1   │ - parseInt(“111110111”,·2);
      1 │ + 0b111110111;
    2 2 │

Number.parseInt("767", 8);

code-block.js:1:1 lint/style/useNumericLiterals  FIXABLE  ━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

  ✖ This call to Number.parseInt() can be replaced by an octal literal.
  
  > 1 │ Number.parseInt(“767”, 8);
      │ ^^^^^^^^^^^^^^^^^^^^^^^^^
    2 │ 
  
  ℹ Using a literal avoids unnecessary computations.
  
  ℹ Unsafe fix: Use the computed octal literal instead.
  
    1   │ - Number.parseInt(“767”,·8);
      1 │ + 0o767;
    2 2 │

Number.parseInt("-1f7", 16);

code-block.js:1:1 lint/style/useNumericLiterals  FIXABLE  ━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

  ✖ This call to Number.parseInt() can be replaced by a hexadecimal literal.
  
  > 1 │ Number.parseInt(“-1f7”, 16);
      │ ^^^^^^^^^^^^^^^^^^^^^^^^^^^
    2 │ 
  
  ℹ Using a literal avoids unnecessary computations.
  
  ℹ Unsafe fix: Use the computed hexadecimal literal instead.
  
    1   │ - Number.parseInt(“-1f7”,·16);
      1 │ + -0x1f7;
    2 2 │

有效

¥Valid

parseInt(1);
parseInt(1, 3);
Number.parseInt(1);
Number.parseInt(1, 3);

0b111110111 === 503;
0o767 === 503;
0x1F7 === 503;

a[parseInt](1,2);

parseInt(foo);
parseInt(foo, 2);
Number.parseInt(foo);
Number.parseInt(foo, 2);

useNumericLiterals

示例

无效

有效

相关链接